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XYZ tires makes automobile tires that have a mean life of 80,000 miles with a standard deviation of 5,000 miles.

1. What fraction of tires is expected to survive beyond 85,000 miles?
2. what percentage of the tires has life between 76,000 and 83,000 miles?
3. what percentage of the tires has a life between 73,000 and 88,000 miles?
4. what fraction will survive fewer than 77,500 miles?
5. what length of warranty is needed so that no more that 5.05 percent of the tires will be expected to fail during the warranty period?
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• Submitted On 07 Nov, 2017 05:07:57
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Z score =(x-u)/std dev 1. ...
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